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JEE (Advance) releases cut-off list

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321624-board2The cut-off score for Jee (Advanced) has been declared at 35% or 177 for the common merit list. The minimum cut-off list for the OBC candidates is 159. For the general category, the scoring marks for each subject is 10, whereas for OBC it is 9 and for SC or ST candidates the maximum scoring marks in each subject is 5 respectively.

It is declared that the students who achieve the required minimum marks for the aggregate cut-off list and each subject cut-off list will make it to the rank list. The scanned copies of the JEE Advanced 2015 have been published online, students can see the cut-offs on www.jeeadv.iitb.ac.in.

In case two candidates gets the same score, then candidate with higher aggregate marks will be assigned a higher rank and if the two candidates have the same aggregate marks, then the candidate having higher score in Maths will be given higher rank.

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